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Zverev ensures leaving the 2026 US Open as the best player of the year

Diego Jiménez Rubio - 12 Sep 2026
Alexander Zverev, best player of 2026. Photo: Getty Images

Alexander Zverev can be very proud of how his season is going and has positioned himself to achieve something that would be a turning point in his career. With his qualification for the final of the US Open 2026, the German tennis player stands at the top of the ATP Race, a ranking that collects the points obtained by players in the current season. The curious thing is that he leads the list with 7,950 points, the same as Jannik Sinner.

The ATP regulations state that in the event of a tie, the player ahead is determined based on points earned in Grand Slam and Masters 1000 titles. Considering that Zverev has reached the semifinals of all four majors, winning one of them, while Sinner missed the US Open and fell in the second round of Roland Garros, the calculations are clear.

Zverev aims to be the 20th player in history to finish a season as number 1

As much as the Italian closes the gap with the Masters 1000, Sascha has a higher overall score in major events, so even if he lost the final, he would appear as the leader of the ATP Race this coming Monday. If he exits New York as the champion, he would be at 8,650 points.

This is very relevant news as a clear objective for Zverev at this point is to finish the season as number 1 in the world. If he manages to win the title at the US Open 2026, the calculations would clarify for him, and he would enjoy a significant competitive advantage over Sinner for the two months of competition remaining this season.

It is important to remember that only 19 players in history know what it is like to finish a year at the top of the world rankings, so it would be a tremendous honor that would greatly enhance the career of Alexander Zverev.

This is an automatic translation. You can read the original news, Zverev se asegura salir del US Open 2026 como el mejor jugador del año